The limiting line in Balmer series for $H$ spectrum will have a frequency of:

3.65 \times 10^{14} s e c^{- 1}

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3.29 \times 10^{15} s e c^{- 1}

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8.22 \times 10^{14} s e c^{- 1}

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- 8.22 \times 10^{14} s e c^{- 1}

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Solution

The correct option is C $8.22 \times 10^{14} s e c^{- 1}$

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