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Question

# The limiting line of Paschen series of H atom will have a frequency equal to: R=1.097×107 m−1

A
3.65×1014 Hz
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B
3.65×1016 Hz
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C
4.95×1017 Hz
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D
3.63×1012 Hz
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Solution

## The correct option is A 3.65×1014 HzThe limiting line will be the shortest line in the Paschen series. It is observed when an electron drops from an orbit with n=∞ to an orbit with n=3. Wave length of this line is given by: 1λ=R(1n12−1n22) Given: R=1.097×107 m−1 Substituting the values of n and R we get: 1λ=1.097×107×(132−1∞2)λ=8.20×10−7m−1 So c = νλ where ν = frequency of the transition ν = 3×1088.20×10−7 = 3.65×1014 Hz

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