The correct option is B 144x2+25y2=3600
12xcosθ+5ysinθ=60⇒x(cosθ5)+y(sinθ12)=1⋯(i)
We know that the tangent to
x2a2+y2b2=1
At point (acosθ,bsinθ) is given by
xcosθa+ysinθb=1⋯(ii)
Comparing (i) and (ii), we get
a=5 and b=12
Hence, the curve is
x225+y2144=1⇒144x2+25y2=3600