The line 2ax+by+3c=0 passes through points of intersection of parabola y2=4x,x2=4y then_______
A
4c2+(a+b)2=0
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B
9c2+(2b+a)2=0
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C
c2+(2a−b)2=0
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D
c2+(2a+b)2=0
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Solution
The correct option is Dc2+(2a+b)2=0 fromthegraphlinepassingthroughintersectionofparabolay=x⇒y−x=0−−−(1)2ax+by+3c=0−−−(2)comparinga=−12,b=1,c=0∴c2+(2a+b)2=0Hence,theoptionDisthecorrectanswer.