The line 2x - 3y + 2 = 0 is perpendicular to another line L $_{1}$ of unknown equation Find the slope of L $_{1}$

\frac{3}{2}

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\frac{- 3}{2}

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\frac{2}{3}

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\frac{- 2}{3}

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none of these

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Solution

The correct option is B $\frac{- 3}{2}$
The slope of line $2 x - 3 y + 2 = 0 i . e y = \frac{2}{3} x + \frac{2}{3}$ is $m = \frac{2}{3}$ .
Since, line $L_{1}$ is perpendicular to this line.
$∴$ its slope is $- \frac{1}{m}$ i.e $- \frac{3}{2}$
Option B is correct.

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The line 2x - 3y + 2 = 0 is perpendicular to another line L1 of unknown equation Find the slope of L1

The correct option is B −32The slope of line 2x−3y+2=0i.ey=23x+23 is m=23.Since, line L1 is perpendicular to this line.∴its slope is −1mi.e −32Option B is correct.

The line 2x - 3y + 2 = 0 is perpendicular to another line L $_{1}$ of unknown equation Find the slope of L $_{1}$

The correct option is B $\frac{- 3}{2}$
The slope of line $2 x - 3 y + 2 = 0 i . e y = \frac{2}{3} x + \frac{2}{3}$ is $m = \frac{2}{3}$ .
Since, line $L_{1}$ is perpendicular to this line.
$∴$ its slope is $- \frac{1}{m}$ i.e $- \frac{3}{2}$
Option B is correct.