The line $2 x - 3 y - 6 = 0$ meets x-axis at

(0, 3)

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(3, 0)

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(2, 3)

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(6, 2)

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Solution

The correct option is B $(3, 0)$
The line $2 x - 3 y - 6 = 0$ meets x-axis,
where $y = 0$ i.e. ordinate is zero
$\Rightarrow 2 x - 3 \times 0 - 6 = 0 \Rightarrow 2 x = 6 \Rightarrow x = 3$
Thus, point of intersection of the line with the x-axis is $(3, 0) .$
Hence, the correct option is (B).

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