The line 2x+y=1 is a tangent to the hyperbola x2a2−y2b2=1. If this line passes through the point of intersection of the directrix and x−axis, then eccentricity of hyperbola is
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Solution
For the line y=−2x+1 to be tangent to hyperbola, 1=a2(−2)2−b2⇒4a2−a2(e2−1)=1⇒e2=5a2−1a2⋯(1) Also, tangent line passes through (ae,0) So, 2a=e ⇒a=e2⋯(2) Solving (1) and (2) we get e=2,e=1 ∴e=2(∵e>1)