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Question

The line 3x3y+17=0 bisects the angle between a pair of lines, where one line is 2x+y+4=0, then the equation of the other line is

A
3x+6y5=0
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B
3x+6y7=0
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C
7xy+14=0
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D
4xy+3=0
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Solution

The correct option is A 3x+6y5=0
Following the figure, we get
tanθ=m2m11+m1m2=31=3
And similarly
tanθ=m1m1+mm1=1m1+m=3

1m=3(1+m) or m1=3(1m)
2=4m or 2m=4
m=12 or m=2
So, equation of line having slope 12 and passing through (293,4) is
3x+6y5=0

Hence, option A

55942_34438_ans_2e9fa795561a4fd6abb0ceab2e081490.png

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