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Opposite Sides of a Parallelogram Are Equal

The line 3x...

Question

The line $3 x + 2 y = 6$ will divide the quadrilateral formed by the lines $x + y = 5, y - 2 x = 8, 3 x y + 2 x = 0$ and $4 y - x = 0$ in

two quadrilaterals

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one pentagon and one triangle

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two traingles

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one triangle and one quadrilateral

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Solution

The correct option is A two quadrilaterals
$\begin{matrix} w e h a v e . . . . . . . . . . . x + y = 5 (d r a w a l i n e o n x - a x i s a n d y - a x i s a s (0, 5) (5, 0) y - 2 x = 8 (d r a w a l i n e o n x - a x i s a n d y - a x i s a s (- 4, 0) (0, 8) 3 y + 2 x = 0 \Rightarrow y = \frac{2 x}{3}, 4 y - x = 0 \Rightarrow y = \frac{x}{4}, \end{matrix}$
we get the quadrilateral point ABCD,
and we find out the $3 x + 2 y = 6$
$\begin{matrix} 3 x + 2 y = 6 - - - - - (i) e q u (i) d i v i d e b y 6 \frac{x}{2} + \frac{y}{3} = 1 t h e n, w e g e t t w o q u a d r i l a t e r a l a s (A F E D, E F B C) S o, t h a t t h e c o r r e c t o p t i o n i s A . \end{matrix}$

Suggest Corrections

Similar questions

3 x + 2 y = 6

x + y = 5, y - 2 x = 8, 3 y + 2 x = 0

4 y - x = 0

(α, 0)

2 x + 5 y = 15

5 x - 4 y = 21

3 x + 5 y + 17 = 0

y = x + 3

α

y = 2 x + 3, y = 0, x = 4

x = 6

(α, 0)

2 x + 5 y = 15, 5 x - 4 y = 21, 3 x + 5 y + 17 = 0

y = x + 3

T R U E

2 x + 3 y = 2, 3 x - 2 y = 4, x + 2 y = 3

2 x - y = 3

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