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Point Slope Form of a Line

The line 3x-4...

Question

The line 3x-4y+7=0 is rotated through an Angle /4 in the clockwise direction about the point (-1,1) The Equation of the line in its new position is

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3 x - 4 y + 7 = 0

is rotated through an angle

\frac{π}{4}

in clockwise direction about the point

(1, 1)

. The equation of the line in its new position is

3 x - 4 y + 8 = 0

is rotated through an angle

\frac{π}{4}

in the clockwise sense about the point

(0, 2)

equation of line in the new position is

3 x - 4 y + 8 = 0

is rotated through an angle

\frac{π}{4}

in the clockwise sense about the point

(0, 2)

. Then the equation of line in the new position is

4 x - 3 y + 2 = 0

is rotated through an angle of

\frac{π}{4}

in clockwise direction about the point

(1, 2) .

The equation of the line in its new position is

Q. If the lines represented by the equation

3 y^{2} - x^{2} + 2 \sqrt{3} x - 3 = 0

are rotated about the point

(\sqrt{3}, 0)

through an angle

15^{0}

, one clockwise direction and other in anti-clockwise direction, then the equation of the pair of lines in the new position is

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