The line 4 – 3 + 12 = 0 meets the -axis at A. Write down the co-ordinates of A. Determine the equation of the line passing through A and perpendicular to 4 – 3 + 12 = 0.

A(-3,0), 4y + 3x + 9 = 0

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A(-2,0), 3y + 9x + 3 = 0

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A(0,-2), 2y + 3x + 6 = 0

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A(2,0), 3y + 4x + 9 = 0

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Solution

The correct option is A
A(-3,0), 4y + 3x + 9 = 0

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