The line 5x − 4y = p intersects X-axis at the point (2, 0). Find the value of p. What are the co-ordinates of the point of intersection of the line and Y-axis?

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Solution

The point (2, 0) satisfies the equation

$5 x - 4 y = p \Rightarrow 5 (2) - 4 (0) = p \Rightarrow 10 - 0 = p \Rightarrow p = 10 . . . . . . . . . . . (1)$

The table containing the values of x and y is given below:

x $-$ 2 2

y $-$ 5 0

From the graph, we can see that the coordinates of the point of the intersection of the line and Y- axis

are (0, $- 2.5$ ).

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The line 5x − 4y = p intersects X-axis at the point (2, 0). Find the value of p. What are the co-ordinates of the point of intersection of the line and Y-axis?

The point (2, 0) satisfies the equation 5x-4y=p⇒5(2)-4(0)=p⇒10-0=p⇒p=10...........(1) The table containing the values of x and y is given below: x -2 2 y -5 0 From the graph, we can see that the coordinates of the point of the intersection of the line and Y- axis are (0,-2.5).