The line $5 x - 4 y = p$ intersects X-axis at the point (2, 0). Find the value of p. What are the co-ordinates of the point of intersection of line and Y-axis?

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Solution

Substituting $(2, 0)$ in the given equation of the line, we get
$5 (2) - 4 (0) = p$
$=> p = 10$
So, the equation of the line is $5 x - 4 y = 10$
The line intersects at the y-axis, when its $x$ cordinate is $0$
So, substituting $x = 0$ in the line, we get
$5 (0) - 4 y = 10$
$y = \frac{- 5}{2}$
Hence, the line intersects the $Y -$ axis at $(0, - \frac{5}{2})$

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The line 5x−4y=p intersects X-axis at the point (2, 0). Find the value of p. What are the co-ordinates of the point of intersection of line and Y-axis?

Substituting (2,0) in the given equation of the line, we get 5(2)−4(0)=p=>p=10So, the equation of the line is 5x−4y=10The line intersects at the y-axis, when its x cordinate is 0So, substituting x=0 in the line, we get 5(0)−4y=10y=−52Hence, the line intersects the Y− axis at (0,−52)

The line $5 x - 4 y = p$ intersects X-axis at the point (2, 0). Find the value of p. What are the co-ordinates of the point of intersection of line and Y-axis?