The line x-41-y-21-z-k2 lies exactly in the plane 2x-4y-z-7- then value of k is

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Condition for Two Lines to Be Parallel

The line x-...

Question

The line $\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$ lies exactly in the plane $2 x - 4 y + z = 7$ , then value of $k$ is

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k

\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}

2 x - 4 y + z = 7

The value of
$k$ such that $\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}$
lies in the plane $2 x - 4 y + z = 7$ is

\frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}

L_{1} : \frac{x - 4}{1} = \frac{y - 2}{1} = \frac{z - k}{2}

2 x - 4 y + z = 7

L_{1}

2 x - 4 y + z = 7,

^{'} k^{'}

\frac{x - 3}{2} = \frac{y + k}{- 1} = \frac{z + 1}{- 5}

2 x - y + z - 7 = 0

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