The line joining A b cos- - b sin- and B a cos- - a sin- is produced to the point Mx- y so that AM - MB-b - a- then x cos- -2-y sin- -2-

The correct option is C 0 As M divides AB externally in the ratio b : a x #160;=b(a cosβ ) a(b cosα )/b a and y= #160;b(a ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Sum of n Terms

The line join...

Question

The line joining A $(b cos α, b sin α)$ and B $(a cos β, a sin β)$ is produced to the point $M (x, y)$ so that $A M : M B = b : a$ , then $x cos \frac{α + β}{2} + y sin \frac{α + β}{2} =$

- 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a^{2} + b^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

A (b cos α, b sin α)

B (a cos β, a sin β)

a \neq b

M (x, y)

A M : M B = b : a

x cos \frac{α + β}{2} + y sin \frac{α + β}{2}

A (b c o s α, b s i n α), B (a c o s β, a s i n β)

x c o s (\frac{α + β}{2}) + y s i n (\frac{α + β}{2})

A

(b cos α, b sin α)

B

(a cos β, a sin β)

M

(x, y)

A M

B M

b : a

x + y tan (\frac{α + β}{2}) = 0

tan α = \frac{a sin β}{1 - a cos β}

tan β = \frac{b sin α}{1 - b cos α}

\frac{sin α}{sin β} = \frac{a}{b}

I f tan α = \frac{a sin β}{1 - a cos β} a n d tan β = \frac{b sin α}{1 - b cos α}

\frac{sin α}{sin β} = \frac{a}{b .}

Join BYJU'S Learning Program