The line joining the centre of a circle to the mid-point of a chord is always perpendicular to the chord. True or False?
A
True
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B
False
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Solution
The correct option is A True
Let the centre of a circle be O. OA and OB are radii AB is any chord with D as the midpoint. In ΔAODandΔBOD, OA = OB (radius) AD = BD (D is mid point of AB) OD = OD (Common) ∴ΔAOD≅ΔBOD(SSS) ⇒∠ODA=∠ODB But they are linear pair. ∴∠ODA=∠ODB=90∘ ⇒OD⊥AB