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Question

The line joining the mid-points of two chords of a circle passes through its centre. Prove that the chords are parallel.

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Solution

E is midpoint of AB and F is midpoint of CD
Given EF passest hrough O (center)
We know that OE is perpendicular to AB (line drawn from center to midpoint of chord is perpendicular to the chord)
OEAB
Similarly OFCD
OEB=OEA=90o and OFD=OFC=90o
EF is transversal for AB and CD and BEF=CFE=90o
interior opposite angles of a tranversal are equal AB is parallel to CD
AB and CD are parallel

1404081_1112560_ans_a0bd005d5b3c4607a54610b4d22290ac.PNG

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