The line joining the points (2,3) and (3,−1) passes through the point (5,−9).
True
Equation of the line through (2,3) and (3,−1) is given by,
Slope = 3−(−1)2−3=4−1=−4
⟹y−3=−4(x−2)
⟹y−3=−4x+8
⟹y+4x=11
If (5,−9) lies on the above line, then the points will satisfy the equation , hence substituting the value of x and y ( 5,9) in y + 4x , we have
L.H.S. = -9+4(5) = -9+20 = 11 = R.H.S.
Hence the line passes through (5,−9).