The line joining the points A2-0 and B3-1 is rotated through an angle of 45-C- about A in the anticlock wise direction- The coordinates of B in the position

The correct option is B (2, √(2)) slop AB = 13 2 = 1 tanθ = 1 i.e., θ = 45^o r = √(2) after rotating turing 45^o angle will beco ...

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Standard XII

Mathematics

Eccentric Angle : Ellipse

The line join...

Question

The line joining the points $A (2, 0)$ and $B (3, 1)$ is rotated through an angle of $45^{\circ} C$ , about $A$ in the anticlock wise direction. The coordinates of $B$ in the position

(2, \sqrt{2})

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(\sqrt{2}, 2)

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(2, 2)

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(\sqrt{2}, \sqrt{2})

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Solution

The correct option is B $(2, \sqrt{2})$
slop $A B = \frac{1}{3 - 2} = 1$
$tan θ = 1$ i.e., $θ = 45^{o}$
$r = \sqrt{2}$
after rotating turing $45^{o}$
angle will become $90^{o}$
find will be let to given
pt. $(2, r) = (2, \sqrt{2})$

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The line joining the points A(2,0) and B(3,1) is rotated through an angle of 45∘C, about A in the anticlock wise direction. The coordinates of B in the position

The correct option is B (2,√2)slop AB=13−2=1tanθ=1 i.e., θ=45or=√2after rotating turing 45oangle will become 90ofind will be let to givenpt. (2,r)=(2,√2)

The line joining the points $A (2, 0)$ and $B (3, 1)$ is rotated through an angle of $45^{\circ} C$ , about $A$ in the anticlock wise direction. The coordinates of $B$ in the position

The correct option is B $(2, \sqrt{2})$
slop $A B = \frac{1}{3 - 2} = 1$
$tan θ = 1$ i.e., $θ = 45^{o}$
$r = \sqrt{2}$
after rotating turing $45^{o}$
angle will become $90^{o}$
find will be let to given
pt. $(2, r) = (2, \sqrt{2})$