The line joining the points (x1,y1) and (x2,y2) subtends a right angle
A
at the point (1,−1) if x1x2+y1y2+2=x1−y1+x2−y2
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B
at the point (−1,1) if x1x2+y1y2+2=y1−x1+y2−x2
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C
at the point (1,1) if x1x2+y1y2+2=x1+y1+x2+y2
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D
at the point (−1,−1) if x1x2+y1y2+2=x1+y1+x2+y2
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Solution
The correct options are A at the point (1,−1) if x1x2+y1y2+2=x1−y1+x2−y2 B at the point (1,1) if x1x2+y1y2+2=x1+y1+x2+y2 D at the point (−1,1) if x1x2+y1y2+2=y1−x1+y2−x2
Given line joining points are (x1,y1) and (x2,y2)
The Line at Point (1,−1) makes right angle So The triangle is formed
Hence m1m2=−1
(y2+1x2−1)(y1+1x1−1)=−1
y2y1+y2+y1+1=−1(x2x1−x2−x1+1)
x1x2+y1y2+2=x1−y1+x2−y2
The Line at Point (−1,1) makes right angle So The triangle is formed
Hence m1m2=−1
(y2−1x2+1)(y1−1x1+1)=−1
y1y2−y2−y1+1=−1(x1x2+x2+x1+1)
x1x2+y1y2+2=y1−x1+y2−x2
The Line at Point (1,1) makes right angle So The triangle is formed