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Question

the line L1 passing through the point(1,1) and the line L2 passes through the point(-1,1) .If the differenceof the slope of the lines is 2.Find the locus of the point of intersection of the line L1 and L2

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Solution

Let the point of intersection be x,ySlope of line L1=y-1x-1Slope of line L2=y-1x+1Difference of slope is 2 .So,y-1x-1-y-1x+1=2y-1x-1-y-1x+1=±2When y-1x-1-y-1x+1=2y-1x+1-x-1y-1x+1x-1=2yx+y-x-1-xy+x+y-1=2x2-22y-2=2x2-2x2-y=0And y-1x-1-y-1x+1=-2y-1x+1-x-1y-1x+1x-1=-2yx+y-x-1-xy+x+y-1=-2x2+22y-2=-2x2+22x2+2y-4=0x2+y=2So, locus of point is x2-y=0 and x2+y=2.

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