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Byju's Answer
Standard XII
Mathematics
Intersection of a Line and Finding Roots of a Parabola
the line L1 p...
Question
the line L1 passing through the point(1,1) and the line L2 passes through the point(-1,1) .If the differenceof the slope of the lines is 2.Find the locus of the point of intersection of the line L1 and L2
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Solution
Let
the
point
of
intersection
be
x
,
y
Slope
of
line
L
1
=
y
-
1
x
-
1
Slope
of
line
L
2
=
y
-
1
x
+
1
Difference
of
slope
is
2
.
So
,
y
-
1
x
-
1
-
y
-
1
x
+
1
=
2
y
-
1
x
-
1
-
y
-
1
x
+
1
=
±
2
When
y
-
1
x
-
1
-
y
-
1
x
+
1
=
2
y
-
1
x
+
1
-
x
-
1
y
-
1
x
+
1
x
-
1
=
2
yx
+
y
-
x
-
1
-
xy
+
x
+
y
-
1
=
2
x
2
-
2
2
y
-
2
=
2
x
2
-
2
x
2
-
y
=
0
And
y
-
1
x
-
1
-
y
-
1
x
+
1
=
-
2
y
-
1
x
+
1
-
x
-
1
y
-
1
x
+
1
x
-
1
=
-
2
yx
+
y
-
x
-
1
-
xy
+
x
+
y
-
1
=
-
2
x
2
+
2
2
y
-
2
=
-
2
x
2
+
2
2
x
2
+
2
y
-
4
=
0
x
2
+
y
=
2
So
,
locus
of
point
is
x
2
-
y
=
0
and
x
2
+
y
=
2
.
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Similar questions
Q.
The line 'l_1' passing through the point
(
1
,
1
)
and the 'l_2' passes through the point
(
−
1
,
1
)
. If the difference of the slope of lines is
2
. Find the locus of the point of intersection of the
l
1
and
l
2
.
Q.
Lines
L
1
and
L
2
are perpendicular that intersect at the point
(
2
,
3
)
. If
L
1
passes through the point
(
0
,
2
)
, then line
L
2
must pass through the point
Q.
A line
L
1
passes through the point
(
1
,
1
)
and
(
2
,
0
)
and another line
L
2
passes through
(
1
2
,
0
)
and perpendicular to
L
1
.
Then the area (in sq. units) of the triangle formed by the lines
L
1
,
L
2
and
y
−
axis is
Q.
A line
L
1
passes through the points
(
1
,
1
)
and
(
2
,
0
)
and another line
L
2
passes through
(
1
2
,
0
)
and is perpendicular to
L
1
.
If the area of the triangle formed by the line
L
1
,
L
2
and
y
−
axis is
p
q
sq. units where
p
,
q
are co-prime, then value of
p
+
q
is
Q.
Let
L
1
:
x
−
1
2
=
y
−
2
1
=
z
−
3
1
L
2
:
x
1
=
y
−
1
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−
5
3
The equation of the line perpendicular to
L
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and
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2
and passing through the point of intersection of
L
1
and
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