The line lx+my+n=0 is normal to the circle x2+y2+2gx+2fy+c=0, if
A
lg+mf+n=0
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B
lg+mf−n=0
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C
lg−mf−n=0
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D
lg−mf+n=0
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Solution
The correct option is Blg+mf−n=0 Given circle is x2+y2+2gx+2fy+c=0 Centre, C=(−g,−f) Line lx+my+n=0 is normal to the given circle, so it passes through the centre, ∴−lg−mf+n=0 ⇒lg+mf−n=0