The line lx + my + n = 0 will be a tangent to the circle x2+y2=a2 iff
A
n2(l2+m2)=a2
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B
a2(l2+m2)=n2
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C
n(l + m) = a
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D
a(l + m) = n
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Solution
The correct option is Ba2(l2+m2)=n2 Line y = mx + c is tangent, if c=±a√1+m2.
Now lx + my + n = 0 or y=−1mx−nm is tangent, if −nm=±a√1+(1m)2orn2=a2(m2+l2).