The line passing through the points (5,1,a) and (3,b,1) crosses the yz− plane at the point (0,172,−132), then
a=6,b=4
Equation of line passing through
(5,1,a) and (3,b,1) is
x−52=y−11−b=z−aa−1=λ.
If line crosses yz-plane i.e., x=0
⇒x=2 λ +5=0
⇒ λ = −5/2,
Since, y=λ(1−b)+1=172
−52(1−b)+1=172⇒b=4
Also, z=λ(a−1)+a=−132⇒a=6.