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Question

The line passing through the points (5,1,a) and (3,b,1) crosses the yz− plane at the point (0,172,−132), then


A

a=2,b=8

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B

a=4,b=6

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C

a=6,b=4

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D

a=8,b=2

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Solution

The correct option is C

a=6,b=4


Equation of line passing through
(5,1,a) and (3,b,1) is
x52=y11b=zaa1=λ.
If line crosses yz-plane i.e., x=0
x=2 λ +5=0
λ = 5/2,
Since, y=λ(1b)+1=172
52(1b)+1=172b=4
Also, z=λ(a1)+a=132a=6.


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