The line plot below shows the different weights of spice packets used in a restaurant. What is the total weight of the $\frac{1}{7}$ lb of spice packets used?

Open in App

Solution

Total amount of $\frac{1}{7}$ lb packets of spices used $= \frac{1}{7} + \frac{1}{7} + \frac{1}{7} + \frac{1}{7} = \frac{4}{7}$ lb

The total amount of $\frac{1}{7}$ lb packets of spices used $\frac{4}{7}$ lb.

Suggest Corrections

Similar questions

The weights of tea in $70$ packets are shown in the following table:
$\begin{matrix} Weights (in grams) & 200 - 01 & 201 - 202 & 202 - 203 & 203 - 204 & 204 - 205 & 205 - 206 Number of packets & 13 & 27 & 18 & 10 & 1 & 1 \end{matrix}$
Find the mean weight of packets using step-deviation method.

Q. The line plot below shows the weight of salt packets used in a restaurant. What is the total weight of the

\frac{1}{5}

lb salt packets used?

Q. The line plot below shows the number of cocoa powder packets used to make cakes. What is the total amount of

\frac{5}{7}

lb packets of cocoa powder used?

Q. The line plot below shows the number of flour packets of different weights. What is the total amount of flour sold by selling

\frac{7}{8}

pound packets?

Q. Amar mixes 112 g of pepper, 215 g of cinnamon and 173 g of cumin to prepare a packet of spice. He prepares 6 such packets. What is the total weight of the packets? (1000 g = 1 kg)

Join BYJU'S Learning Program

The line plot below shows the different weights of spice packets used in a restaurant. What is the total weight of the 17 lb of spice packets used?

Total amount of 17 lb packets of spices used =17+17+17+17=47 lb The total amount of 17 lb packets of spices used 47 lb.

The line plot below shows the different weights of spice packets used in a restaurant. What is the total weight of the $\frac{1}{7}$ lb of spice packets used?

Total amount of $\frac{1}{7}$ lb packets of spices used $= \frac{1}{7} + \frac{1}{7} + \frac{1}{7} + \frac{1}{7} = \frac{4}{7}$ lb

The total amount of $\frac{1}{7}$ lb packets of spices used $\frac{4}{7}$ lb.