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Byju's Answer
Standard XII
Mathematics
Obtaining Centre and Radius of a Circle from General Equation of a Circle
The line r=...
Question
The line
r
=
a
+
t
b
touches the sphere
r
2
−
2
r
.
c
+
h
=
0
,
c
2
>
h
at the point with position vector
a
if
A
(
a
−
b
)
.
c
=
0
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B
(
a
−
c
)
.
b
=
0
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C
(
b
−
c
)
.
a
=
0
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D
a
.
b
+
b
.
c
+
c
.
a
=
0
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Solution
The correct option is
C
(
a
−
c
)
.
b
=
0
Given
r
=
a
+
t
b
touches the sphere
r
2
−
2
r
c
+
h
=
0
r
2
−
2
r
c
+
h
=
0
Add
c
2
on both sides
(
r
−
c
)
2
=
c
2
−
h
centre of sphere is
c
Let
r
=
a
+
t
b
touches sphere at
a
d.r's of line joining
a
and
c
is
(
a
−
c
)
d.r's of
r
=
a
+
t
b
is
b
as both are perpendicular
Dot product of d.r's
=
0
(
a
−
c
)
b
=
0
Suggest Corrections
0
Similar questions
Q.
If
¯
¯
¯
a
,
¯
¯
b
,
¯
¯
c
, are unit vectors such that
¯
¯
¯
a
+
¯
¯
b
+
¯
¯
c
=
¯
¯
¯
0
, then
¯
¯
¯
a
.
¯
¯
b
+
¯
¯
b
.
¯
¯
c
+
¯
¯
c
.
¯
¯
¯
a
=
Q.
If
→
a
,
→
b
,
→
c
are unit vectors such that
→
a
+
→
b
+
→
c
=
0
, find the value of
→
a
.
→
b
+
→
b
.
→
c
+
→
c
.
→
a
.
Q.
If
¯
¯
¯
a
,
¯
¯
b
,
¯
¯
c
are three vectors such that
|
¯
¯
¯
a
|
=
1
,
|
¯
¯
b
|
=
2
,
|
¯
¯
c
|
=
3
, and
¯
¯
¯
a
.
¯
¯
b
=
¯
¯
b
.
¯
¯
c
=
¯
¯
c
.
¯
¯
¯
a
=
0
, then
|
[
¯
¯
¯
a
¯
¯
b
¯
¯
c
]
|
=
Q.
The line
→
r
=
→
a
+
t
→
b
touches the sphere
→
r
2
−
2
→
r
.
→
c
+
h
=
0
,
c
2
>
h
at the point with position vector
→
a
is
Q.
If
→
a
,
→
b
,
→
c
are unit vectors such that
→
a
+
→
b
+
→
c
=
→
0
, then the value of
→
a
.
→
b
+
→
b
.
→
c
+
→
c
.
→
a
is equal to
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