The line through A (-2, 3) and B(4, b) is perpendicular to the line 2x - 4y = 5. Find the value of b.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

-9

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

-8

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C -9
Given; A(-2, 3) and B (4, b)
Slope of the line AB $m_{1}) = \frac{y_{2} - y_{1}}{x_{2} - x_{1}} = \frac{b - 3}{4 + 2} = \frac{b - 3}{6}$
Slope of the line $(m_{2}), 2 x - 4 y - 5 = 0 = \frac{- 2}{- 4} = \frac{1}{2}$
Since both these line are perpendicular, so, $m_{1} . m_{2} = - 1$
$\Rightarrow (\frac{b - 3}{6}) . \frac{1}{2} = - 1 \Rightarrow \frac{b - 3}{12} = - 1 \Rightarrow b - 3 = - 12 \Rightarrow b = - 12 + 3 \Rightarrow b = - 9$

Suggest Corrections

Similar questions

A (- 2, 3)

B (4, b)

2 x - 4 y = 5

| b |

The line through A(–2, 3) & B(4, b) is perpendicular to the line 2 – 4y = 5. Find the value of ‘b’

A line through A(-2,6) and B(4,b) is perpendicular to the line 2x - 4y = 5. The value of b is ___.

Find the equation of line passing through (2, 3) and perpendicular to the line 3x + 4 y - 5 = 0.

Join BYJU'S Learning Program