The line through P(5, 3) intersects y-axis at Q.

(i) Write the slope of the line.

(ii) Write the equation of the line.

(iii) Find the co-ordinates of Q.

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Solution

The slope of the line is
tan Q =tan 45=1=m

(ii)as we know equation of line is

y-y1=m(x-x1)
y-3=x-5
X-y=2

(iii)since x =0 as point Q is on y axis

so putting value in eq of line

y=-2
so
Q =(0,-2)

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The line through P(5, 3) intersects y-axis at Q. (i) Write the slope of the line. (ii) Write the equation of the line. (iii) Find the co-ordinates of Q.

The slope of the line is tan Q =tan 45=1=m (ii)as we know equation of line is y-y1=m(x-x1) y-3=x-5 X-y=2 (iii)since x =0 as point Q is on y axis so putting value in eq of line y=-2 so Q =(0,-2)

The line through P(5, 3) intersects y-axis at Q.

(i) Write the slope of the line.

(ii) Write the equation of the line.

(iii) Find the co-ordinates of Q.

The slope of the line is
tan Q =tan 45=1=m

(ii)as we know equation of line is

y-y1=m(x-x1)
y-3=x-5
X-y=2

(iii)since x =0 as point Q is on y axis

so putting value in eq of line

y=-2
so
Q =(0,-2)