Question

The line $x+6y=12$ cuts the X and Y axis at $(a,0)$ and $(0,b)$ respectively. The value of $a+b$ is ___.

• A. 6
• B. 8
• C. 12
• D. 14

Answer 1

The correct option is D 14

The line $x+6y=12$ cuts the X and Y axis at $(a,0)$ and $(0,b)$ respectively.

$⟹$$(a,0)$ and $(0,b)$ are solutions of line $x+6y=12$


Substitute $(a,0)$ in the line
$a+6\times 0=12$
$⟹a=12$

Similarly, substitute $(0,b)$ in the line
$0+6\times b=12$
$⟹b=2$

Hence, $a+b=12+2=14$