Question

The linear charge density of four quadrants of a ring of radius R is as shown. Electric field at the centre will be :

• A. Zero
• B. $\frac{2\sqrt{K}\lambda }{R}$
• C. $\frac{4\sqrt{2}K\lambda }{R}$
• D. $\frac{4K\lambda }{R}$

Answer 1

The correct option is D $\frac{4K\lambda }{R}$

Field due to a semicircular uniform charge is $\frac{2K\lambda }{R}$
Thus field at center due this configuration is $\frac{4K\lambda }{R}$