The linear density of a vibrating string is $1.3 \times 10^{- 4} k g / m$ . A transverse wave is propagating on the string and is described by the equation $y = 0.021 sin (x + 40 t)$ where $x$ and $y$ are in meters and $t$ in seconds. The tension in the string is :

0 .21 N

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0.48 N

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0.12 N

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4.8 N

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Solution

The correct option is A $0 .21 N$
$v = \frac{w}{K} = 40 = \sqrt{\frac{T}{μ}}$
$T = μ v^{2}$
$= 1.3 \times 10^{- 4} \times 1600$
$= 0.208$
$≃ 0.21 N$

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Q. The linear density of a vibrating string is

1.3 \times 10^{- 4} k g / m

. The transverse wave propagating along the string is described by

y = 0.021 sin (x + 30 t)

where

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is in meter and

t

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The linear density of a vibrating string is $10^{- 4} k g / m$ . A transverse wave is propagating on the string, which is described by the equation y = 0.02 sin (x + 30 t), where x and y are in meters and time t in seconds. Then tension in the string is