Question

The linear equation that converts Fahrenheit ${(}^{o}F)$ to Celsius ${(}^{o}C)$ is given by the relation: ${}^{c}C=\frac{5F-160}{9}$, then what is the numerical value of temperature which is same in both the scales?

Answer 1

$\frac{{}^{0}C}{5}=\frac{F-32}{9}$

$letiff{=}^{0}C$

$\frac{9^{0}C}{5}{=}^{0}C-32$

$9^{0}C-5^{0}C=-160$

$4^{0}C=-160$

${}^{0}C=-40$