The linear factors of the equation x2 y2-9 x2-25 y2-225-0 is-are A- y-3-0B- y -3-0C- x-5-0D- x -5-0

The correct options are A (y 3)= 0 nbsp; B (y+3)= 0 C (x 5)= 0 D (x+5)= 0 nbsp;x^2y^2 9x^2 25y^2 + 225 = 0 ⇒ x^2 (y^2 9) 25(y^2 9) = 0 ⇒ (y^2 9)(x^ ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Higher Order Equations

The linear fa...

Question

The linear factor(s) of the equation $x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$ is/are

(y - 3) = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(y + 3) = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x - 5) = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(x + 5) = 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct options are
A $(y - 3) = 0$
B $(y + 3) = 0$
C $(x - 5) = 0$
D $(x + 5) = 0$
$x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$
$\Rightarrow x^{2} (y^{2} - 9) - 25 (y^{2} - 9) = 0$
$\Rightarrow (y^{2} - 9) (x^{2} - 25) = 0$
$\Rightarrow (y - 3) (y + 3) (x - 5) (x + 5) = 0$

Suggest Corrections

Similar questions

Q. The linear factor(s) of the equation

x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0

is/are

Q. Equation of the tangent to

y^{2} = 8 x

which is parallel to x-y+3=0 is

Q. The equation of a line passing through

(- 2, 3)

and parallel to the tangent at origin for circle

x^{2} + y^{2} + x - y = 0

is:

The Equation y = - 5, in two variables can be written in the form of ax + by + c = 0 as

Q. The foci of the hyperbola are

S (5, 6), S^{'} (- 3, - 2)

. If its eccentricity is

2

, then the equation of its directrix corresponding to focus

S

Join BYJU'S Learning Program

Explore more

Higher Order Equations

Standard XII Mathematics

Join BYJU'S Learning Program

The linear factor(s) of the equation x2y2−9x2−25y2+225=0 is/are

The correct options are A (y−3)=0 B (y+3)=0 C (x−5)=0 D (x+5)=0 x2y2−9x2−25y2+225=0 ⇒x2(y2−9)−25(y2−9)=0 ⇒(y2−9)(x2−25)=0 ⇒(y−3)(y+3)(x−5)(x+5)=0

The linear factor(s) of the equation $x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$ is/are

The correct options are
A $(y - 3) = 0$
B $(y + 3) = 0$
C $(x - 5) = 0$
D $(x + 5) = 0$
$x^{2} y^{2} - 9 x^{2} - 25 y^{2} + 225 = 0$
$\Rightarrow x^{2} (y^{2} - 9) - 25 (y^{2} - 9) = 0$
$\Rightarrow (y^{2} - 9) (x^{2} - 25) = 0$
$\Rightarrow (y - 3) (y + 3) (x - 5) (x + 5) = 0$