The linear magnification of a convex mirror is 12.5 cm. How far is its center of curvature (i) from the pole (ii) from the focus

Open in App

Solution

since lenear magnification have no unit but in question it has unit cm
so it will be focal length
so focal length F=12.5cm
(1)the distance between pole and centre of curvature is radius of curvature(R)
R=2F=2 x 12.5cm = 25cm
(2)focus is the mid point of pole and centre of curvature
so distance from focus to centre of curvarure = F = 12.5 cm

Suggest Corrections

Similar questions

Q. How does the magnitude of magnification changes if an object placed at center of curvature of a concave mirror is moved towards the focus?

How will the magnitude of magnification change if an object placed at center of curvature is moved towards focus in concave mirror?

How will the magnitude of magnification change, if an object placed at the center of curvature of a concave mirror is moved towards the focus?

How will the magnitude of magnification change if an object placed at center of curvature of a concave mirror is moved towards focus in the case of a concave mirror?

Q. A concave mirror produces magnification of +4. The object is placed:

(a) at the focus
(b) between focus and centre of curvature
(c) between focus and pole
(d) beyond the centre of curvature

Join BYJU'S Learning Program