CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The linear momentum of a body is increased by 10 %. What is the percentage change in its kinetic energy?

A
15%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
17%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
21%
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
27%
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is D 21%
As momentum is mass x velocity.
So 10% increase in momentum means10% increase in velocity.
So, if initial velocity is v, then new velocity is 1.1v
Thus initial K.E. Ki=mv2/2.
Final K.E. Kf=m(1.1v)2/2=1.21mv2/2=1.21Ki
Change in K.E. is (KfKi)/Ki=0.21=21%

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
A Sticky Situation
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon