The linear momentum of a particle is given by P- asin t - i -acos t - j kg- m - s- A force - F is acting on the particle- Select correct alternative-s-

The correct option is B Linear momentum → P of particle is always perpendicular to → F Linear momentum #160; P⃗=asintî acostĵ F⃗=dP⃗dt=a ...

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Standard IX

Physics

Second Law of Motion

The linear mo...

Question

The linear momentum of a particle is given by $P = (a sin t \land i - a cos t \land j) k g - m / s$ . A force $\to F$ is acting on the particle. Select correct alternative/s:

Linear momentum

\to P

of particle is always parallel to

\to F

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Linear momentum

\to P

of particle is always perpendicular to

\to F

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Linear momentum

\to P

is always constant

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Magnitude of linear momentum is constant with respect to time.

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None of the above

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Solution

The correct option is B Linear momentum $\to P$ of particle is always perpendicular to $\to F$
Linear momentum $\to P = a s i n t^i - a c o s t^j$
$⟹ \to F = \frac{d \to P}{d t} = a c o s t^i + a s i n t^j$
$\to F . \to P = 0$
Thus $\to F$ and $\to P$ are perpendicular to each other.

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The linear momentum of a particle is given by P=(asint∧i−acost∧j)kg−m/s. A force →F is acting on the particle. Select correct alternative/s:

The correct option is B Linear momentum →P of particle is always perpendicular to →FLinear momentum →P=asint^i−acost^j⟹→F=d→Pdt=acost^i+asint^j→F.→P=0Thus →F and →P are perpendicular to each other.

The linear momentum of a particle is given by $P = (a sin t \land i - a cos t \land j) k g - m / s$ . A force $\to F$ is acting on the particle. Select correct alternative/s:

The correct option is B Linear momentum $\to P$ of particle is always perpendicular to $\to F$
Linear momentum $\to P = a s i n t^i - a c o s t^j$
$⟹ \to F = \frac{d \to P}{d t} = a c o s t^i + a s i n t^j$
$\to F . \to P = 0$
Thus $\to F$ and $\to P$ are perpendicular to each other.