Question

The linear momentum of an electron revolving in the $2^{nd}$ Bohr orbit is given by $p=Kh$ where, $h$ is the Planck's Constant. Predict the radius of the orbit.

• A. $K\pi$
• B. $\frac{1}{K\pi }$
• C. $\frac{K}{\pi }$
• D. $\frac{\pi }{K}$

Answer 1

The correct option is B $\frac{1}{K\pi }$

Wavelength of the electron wave is given by:
$\lambda =\frac{h}{p}=\frac{h}{Kh}$
$\therefore \lambda =\frac{1}{K}$
We know that,
$2\pi r=n\lambda$
For $2^{nd}$ Bohr's orbit
$r=\frac{2\times 1}{K\times 2\times \pi }=\frac{1}{K\pi }$