Question

The linear velocity of a point on the surface of earth at a latitude of ${60}^0$ is:

• A. $\frac{800}{3}m/s$
• B. $\frac{800\pi }{3}m/s$
• C. $800\times \frac{5}{18}m/s$
• D. $\frac{2000\pi }{27}m/s$

Answer 1

The correct option is D $\frac{2000\pi }{27}m/s$

$\omega =\frac{2\pi }{24\times 60\times 60}rad/s$

Radius of horizontal circle $=r=\frac{R}{2}$ $[R=6400Km]$

$V=\omega r$ [Because it is at ${60}^o$ latitude}

$=\frac{2\pi }{24\times 60\times 60}\times \frac{6400\times 1000}{2}m/s$

$=\frac{2000\pi }{27}m/s$