The lines 2x-3y=5 and 3x-4y=7 are the diameters of a circle of area 154 square units. The equation of the circle is
Centre of circle = Point of intersection of diameters =(1,-1)
Now area =154 ⇒πr2=154⇒r=7
Hence the equation of required circle is
(x−1)2+(y+1)2=72⇒x2+y2−2x+2y=47