The lines $3 x + 4 y + l = 0$ and $6 x + 8 y + m = 0$ are tangents to the same circle. The radius of the circle is

| 2 λ - μ | / 20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| 2 λ + μ | / 10

No worries! We‘ve got your back. Try BYJU‘S free classes today!

| 2 λ + μ | / 20

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D none of these
$3 x + 4 y + l = 0 | O P | = \frac{- 3 g - 4 f + l}{\sqrt{3^{2} + 4^{2}}} = \frac{- 3 g - 4 f + l}{5} | O D | = \frac{- 6 g - 8 f + m}{10} | O P | = | O D | \frac{- 3 g - 4 f + l}{5} = \frac{- 6 g - 8 f + m}{10} - 6 g - 8 f + 2 l = - 6 g - 8 f + m 2 l - m 2 l = m 3 a + 4 y = - l \times 2 6 x + 8 y = - 2 l \times 1 6 x + 8 y = - 2 l 6 x + 8 y = - 2 l$

Suggest Corrections

Similar questions

| {log}_{2} x + 1 | + ∣ ∣ 1 - ({log}_{2} x)^{2} ∣ ∣ = ∣ ∣ {log}_{2} x + ({log}_{2} x)^{2} ∣ ∣,

x

{λ} \cup [μ, \infty) .

| {log}_{2} x + 1 | + | 1 - {log}_{2}^{2} x | = | {log}_{2} x + {log}_{2}^{2} x |,

x

{λ} \cup [μ, \infty) .

3 x + 4 y = 9

6 x + 8 y + 15 = 0

3 x - 4 y + 4 = 0

6 x - 8 y - 7 = 0

3 x - 4 y = 4

6 x - 8 y - 7 = 0

Join BYJU'S Learning Program