The lines acosθ+2asinθ+1r=0,bcosθ+3bsinθ+1r=0 and ccosθ+4csinθ+1r=0 are concurrent then a,b,c are in
A
A.P.
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B
G.P.
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C
H.P.
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D
A.G.P
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Solution
The correct option is D H.P. Given line are concurrent acosθ+2asinθ+1r=0 bcosθ+3bsinθ+1r=0 ccosθ+4csinθ+1r=0 ⇒∣∣
∣∣a2a1b3b1c4c1∣∣
∣∣=0 ⇒ab+bc=2ac ⇒2b=1a+1c Hence, 1a,1b,1c are in AP. a,b,c are in H.P.