The lines are
$y = 5 x - 3; y = 4 - 2 x; 2 x + 3 y = 8$

Concurrent

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Coincident

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Parallel

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None of these

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Solution

The correct option is A Concurrent
Given,
$y = 5 x - 3$ ........eq $1$
$y = 4 - 2 x$ ...............eq $2$
To find the intersection of these two lines, equate the RHS of both the equations
$5 x - 3 = 4 - 2 x$
$7 x = 7,$ or $x = 1$
hence, $y = 2$
Put $x = 1$ and $y = 2$ in the third equation:
$2 x + 3 y = 8$
$2 + 6 = 8$
$8 = 8$
Hence, the three lines are concurrent, as they intersect at a single point.

Suggest Corrections

Similar questions

y = 5 x - 3

y = 4 - 2 x

2 x + 3 y = 8

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-

1. {(3 x - y)}^{2} - ({5 x}^{2} - 2 x y)

2. {(2 x - y)}^{2}

3. {(2 x + y)}^{2} - 2 x y

4. {(2 x + 3 y)}^{2} - 8 y (2 x + y)

5 x - 3 y = 2

2 x + y = 3

2 x + 3 y - 8 = 0

5 x - y + 7 = 0

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