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Question

The lines ax+by+c=0, bx+cy+ca=0 and cx+ay+b=0 are concurrent if

A
a3=3abc
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B
a2=abc
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C
a3=bc
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D
None of these
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Solution

The correct option is A a3=3abc
Given the equations of the lines are,
ax+by+c=0......(1)
bx+cy+a=0......(2)
cx+ay+b=0......(3).
Now these three lines will be concurrent if,
∣ ∣abcbcacab∣ ∣=0
Or, (abca3)(b3abc)+(abcc3)=0
Or, a3+b3+c3=3abc
Or, a3=3abc.

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