Question

The lines $\frac{x-1}{1}-\frac{y+3}{-3}=\frac{z-6}{6}$ and $\frac{x+1}{-1}=\frac{y-1}{1}=\frac{z-6}{6}$ intersect at

• A. (1,- 3, 6)
• B. (-1, 1, 6)
• C. (0, 0, 0)
• D. No point

Answer 1

The correct option is C (0, 0, 0)

$(\lambda +1.-3\lambda -3,6\lambda +6)$
$(-\mu -1,\mu +1,6\mu +6)$
$\lambda +1=-\mu -1-3\lambda -3=\mu +1$
$\lambda +\mu +2=0\mu +3\lambda +4=0$
$\lambda =\mu$
$\therefore \lambda =\mu =-1$
(0, 0, 0)