The lines x-1 - y-2 - z-3 and x -1-2 - y - 2-4 - z -3-6 are -

The correct option is C intersecting L_1 = #10;x x_1a_1 = y y_1b_1 = z z_1 #10;c_1 = x 1 = y 2 = z 3 #10; #10; #160; #160; #160; ...

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The lines x...

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The lines $\frac{x}{1} = \frac{y}{2} = \frac{z}{3}$ and $\frac{x - 1}{- 2} = \frac{y - 2}{- 4} = \frac{z - 3}{- 6}$ are :-

Coincident

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skew

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intersecting

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parallel

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Similar questions

\frac{x}{1} = \frac{y}{2} = \frac{z}{3}

\frac{x - 1}{- 2} = \frac{y - 2}{- 4} = \frac{z - 3}{- 6}

\frac{x + 3}{- 4} = \frac{y - 6}{3} = \frac{z}{2}

\frac{x - 2}{- 4} = \frac{y + 1}{1} = \frac{z - 6}{1}

\frac{x - 1}{1} = \frac{y - 2}{2} = \frac{z - 3}{3}

\frac{x + 1}{1} = \frac{y}{3} = \frac{z}{4}

\frac{x}{1} = \frac{y}{2} = \frac{z}{3}

\frac{x - 1}{3} = \frac{y - 2}{- 1} = \frac{z - 3}{4}

\frac{x + k}{3} = \frac{y - 1}{2} = \frac{z - 2}{h}

\frac{x - 4}{2} = \frac{y + 1}{- 3} = \frac{z}{6}

\frac{x}{- 1} = \frac{y - 1}{\frac{3}{2}} = \frac{z + 1}{- 3}

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