The lines given by the equation $(2 y^{2} + 3 x y - 2 x^{2}) (x + y - 1) = 0$ form a triangle which is :

equilateral

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isosceles

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right angled

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obtuse angled

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Solution

The correct option is C right angled
Given $2 y^{2} + 3 x y - 2 x^{2} = 0$
These pair of straight lines intersect at right angle as the sum of the coefficients of $y^{2}$ and $x^{2}$ is $0.$
Hence, the triangle formed by these lines and $x + y - 1 = 0$ is a right triangle .

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