CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

The lines joining the points of intersection of the curve (xh)2+(yk)2c2=0 and the line kx + hy = 2hk to the origin are perpendicular, then



A

loader
B

loader
C

loader
D

loader

Solution

The correct option is B


The line is x2h+y2k=1 and circle is, 

x2+y22(hx+ky)+(h2+k2c2)=0

Making it homogeneous, we get

(x2+y2)2(hx+ky)(x2h+y2k)+(h2+k2c2)(x2h+y2k)2=0

If these lines be perpendicular, then A + B = 0

[11+(h2+k2c2)4h2]+[11+(h2+k2c2)4k2]=0

or (h2+k2c2)(h2+k24h2k2)=0

h2+k2=c2.


Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image