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Question

The lines L1 and L2 denoted by 3x2+10xy+8y2+14x+22y+15=0 intersect at the point P and have gradients m1 and m2 respectively. The acute angles between them is θ. Which of the following relations hold good ?

A
m1+m2=5/4
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B
m1m2=3/8
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C
Acute angle between L1 and L2 is sin1(255).
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D
Sum of the abscissa and ordinate of the point P is 1.
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Solution

The correct options are
B m1m2=3/8
C Acute angle between L1 and L2 is sin1(255).
D Sum of the abscissa and ordinate of the point P is 1.
3x2+10xy+8y2+14x+22y+15=0 ----- (1)

3x2+10xy+8y2=0

3x2+6xy+4xy+8y2=0

3x(x+2y)+4y(x+2y)=0

(3x+4y)(x+2y)=0

(4y+3x+c1)(2y+x+c2)=0

4yc2+3xc2+2yc1+xc1+8y2+3x2+10xy+c1c2=0 ----- (2)

3x2+10xy+8y2+4yc2+3xc2+8yc1+xc1+c1c1=0

on comparing equation (1) and (2)

3c2+c1=14 ---- (3)

4c2+2c1=22 ---- (4)

From equation 3 and 4

c1=5,c2=3

3x2+10xy+8y2=0

8y2+10xy+3x2=0

y2+108xy+38x2=0

y2+(m1+m2)xy+m1m2x2=0

m1+m2=ba=108=54 ----- (5)

m1m2=ca=38 ---- (6)

tanθ=|m1m21+m1m2|=|12+341+38|=211

sinθ=255

4y+3x+5=0 ----- (7)

2y+x+3=0 ----- (8)

then,

x=1,y=2

Sum =x+y=1

Hence the correct options are B,C and D.

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