The lines representing the linear equations 2x−y−3 and 4x−y=5
A
intersect at a point
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B
are parallel
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C
are coindicent
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D
intersect at exactly two points
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Solution
The correct option is A intersect at a point The given lines are 2x−y=3 Here a1=2,b1=−1,c1=3 and 4x−y=5 Here a2=4,b2=−1,c2=5 ∴a1a2=24=12 and b1b2=1 ∵a1a2≠b1b2 Thus, lines will intersect at a point. Hence the correct option is (A).