The lines with equation 2x - 3y = 8 and -x + 4y = 2 are perpendicular to each other.

True

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False

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Solution

The correct option is B
False

$2 x - 3 y = 8$

$\Rightarrow y = \frac{2 x}{3} - \frac{8}{3} [∴ m_{1} = \frac{2}{3}]$

$- x + 4 y = 2$

$\Rightarrow y = \frac{x}{4} + \frac{1}{2} [∴ m_{2} = \frac{1}{4}]$

$∵ m_{1} \times m_{2} \neq - 1$

So,given lines are not perpendicular.

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Similar questions

The graphs of the equations 2x+3y-2=0 and x-2y-8=0 are two lines which are

(a) coincident

(b) parallel

(d) perpendicular to each other

Find the value of p if the lines, whose equations are 2x - y + 5 = 0 and px + 3y = 4 are perpendicular to each other.

2 x + 3 y - 2 = 0 and x - 2 y - 8 = 0

2 x - 3 y = 8

- x + 4 y = 2

2 x + 3 y + 7 = 0

x^{2} + y^{2} - 2 x + 4 y + 1 = 0

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